' New Point(200, 20) = destination for upper-left point of original Draw the image mapped to the parallelogram.Į.Graphics.DrawImage(image, destinationPoints) Draw the image unaltered with its upper-left corner at (0, 0). Point destinationPoints = // destination for lower-left point of The following example produces the images shown in the first illustration. The following illustration shows a similar transformation applied to a metafile: The following illustration shows a similar transformation applied to a photographic image: The y-axis along the left edge of the original image is mapped to the line that runs through (200, 20) and (250, 30). The x-axis along the top edge of the original image is mapped to the line that runs through (200, 20) and (110, 100). The original image has been skewed, reflected, rotated, and translated. The following illustration shows the original image and the image mapped to the parallelogram. Now suppose you map those three points to destination points as follows. Exampleįor example, suppose the original image is a rectangle with upper-left corner at (0, 0), upper-right corner at (100, 0), and lower-left corner at (0, 50). The three destination points determine an affine transformation that maps the original rectangular image to a parallelogram. You can rotate, reflect, and skew an image by specifying destination points for the upper-left, upper-right, and lower-left corners of the original image.
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